8. (4 points) Men’s heights are normally distributed with mean 68.0 inches and standard deviation 3.0 inches. What is the 90th percentile for man’s heights? (Show work and round the answer to 2 decimal places)
Finding 90*” percentile Nermsl Distributienp = fifl cr=3 cit:II“E 90m percentile is given by: Pm = ’11. + cr K ineNermmfl} p = {33 , cr = 3 , Fclr 90th percentile, ineNermrfflQ} = 1.232…