i need help with this homework programs all of them.
Problem 1a)Mean = 6.49 hoursStandard deviation = 1.05/sqrt(150) = 0.0857 hoursb)Probability of coming up with a sample that they studies 6 hours or less = P ( z < (6 – 6.49)/0.0857 )= P(…
i need help with this homework programs all of them.
Problem 1a)Mean = 6.49 hoursStandard deviation = 1.05/sqrt(150) = 0.0857 hoursb)Probability of coming up with a sample that they studies 6 hours or less = P ( z < (6 – 6.49)/0.0857 )= P(…
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