Mars, Inc. states that 16% of all milk chocolate M&M’S® produced are green. A group of students took the following samples from a bowl of 500 mixed up M&M’S®.
SAMPLE DATA ANALYSIS
Twenty samples were collected for sample sizes n = 30 and n = 60. The results and corresponding dot plots are shown below.
- What is the population parameter of interest in the investigation?
- Why can we not realistically calculate the population parameter of interest directly?
- How could the concept of random sampling be used to investigate the population parameter of interest?
- What are we interested in finding out about each of the samples of M&M’S®?
- What information do we need in order to answer our question or investigate the claim that 16% of milk chocolate M&M’S® produced by Mars, Inc. are green? How can we use the samples of M&M’S® to obtain this information?
- What value is at the center of the dot plot constructed by using one sample per group? Is it a coincidence that the value is close to/far from the 16% claimed by Mars, Incorporated?
- Mars, Inc. claimed that 16% of milk chocolate M&M’S® produced are green. Does the information on the dot plot seem to support this claim? Why or why not?
- Attachment 1
- Attachment 2
Sample Proportions forn = 30Sample Proportions form = 60Sample # Proportion of green MakersSample & Proportion of green Meters5 / 30 = 0 . 1712/60 = 0.205/30 = 0.2015 / 60 = 0.253/ 30 = 0.1014160 = 0. 238 / 30 = 0 .277 / 60 = 0 . 123/ 30 = 0.1010 / 60 = 0 .173/ 30 = 0.1010 /60 = 0.176/30 = 0. 211 /60 = 0.185/30 = 0.177/ GO = 0.127130 = 0 233 / GO = 0.133/ 30 = 0.1010 / 60 = 0.173/ 30 = 0.103/ 60 = 0.134/ 30 = 0 .1311/ 60 = 0.187 / 30 = 0.236/ 60 = 0.105/ 30 = 0 .1711/ 60 = 0.185/ 30 = 0.1712/ 60 = 0.201/30 = 0.0310 / 60 = 0.176 / 30 = 1 2012/ 60 = 0.203/ 30 = 1 2721/ 60 = 0.18130 = D.0313/ 60 = 0.225/30 = 1 173/ 50 = 0.13