Section 9.122 a) – dThe prompt asked: Which of the following represents a reasonable interpretation of the survey results? For those not reasonable, explain the flaw.Section
9.2
You can use the tables in the back of the book or Google t-value tables. Use the degrees of freedom and the area given to find t-value
Section 9.37) x-bar = 54 Margin of error, E = (sd*z_c)/sqrt(n) = (8*1.96)/Sqrt(40) = ? sd= 8 n = 40 z_c = 1.96
95% Cl = (x-bar – E; x-bar + E) = ?
12) x-bar = 93.43 Margin of error, E = s.e * Za = 15/sqrt(40) = ? sd = 15 n = 40
99% Cl = (x-bar – E; x-bar + E) = ?