Section 9.122 a)  – dThe prompt asked: Which of the following represents a reasonable interpretation of the survey results? For those not reasonable,  explain the flaw.Section 

9.2 

You can use the tables in the back of the book or Google t-value tables. Use the degrees of freedom and the area given to find t-value

Section 9.37) x-bar = 54  Margin of error, E = (sd*z_c)/sqrt(n) =  (8*1.96)/Sqrt(40)  = ?  sd= 8  n = 40  z_c = 1.96

95% Cl = (x-bar – E;  x-bar + E)  = ?

12) x-bar = 93.43  Margin of error, E = s.e * Za = 15/sqrt(40) = ?  sd = 15  n = 40

99% Cl = (x-bar – E;   x-bar + E)  = ?

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