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The sample space given here shows all possible sequences for a family with 4 children. where B EGGS 5353 5553 GEES BEBE ‘3 stands for boy and G stands for girl. It all 15 5535 GBGB BIS EBoutcomes are equally likely, find the probability that there are: 5365 GBBG EBGBa. exactly [1 boys. by BEECH}! 1 girl, EGGS BGGB BEBEo. exactly 2 girls. BGBG d. exactly 3 girls. e. exactly 4 girls. BEES e. The probability of exactly fl boys is E. {Type an integer or a simplified fraction}b. The probability of exactly 1 girl is El. {Type an integer or a simplified traction}o. The probability of exactly 2 girls is D. {Type an integer or a simplified fraction.)d. The probability of exactly 3 girls is E {Type an integer or a simplified traction.) e. The probability of exactly 4 girls is El {Type an integer or a simplified traction.)