Use the laws of logic to prove that ¬(p∧ q) ∨ (¬p∧ q)== ¬p∨¬q

( p q ) (p q) (p q) (p q) (demorgan’s law) ((p q) p )) ((p q ) q )) (p q) (p (q q)) (p q ) (p T ) ( p q ) T (p q ) (distributive law)

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